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Q: How do you calculate the force required to pull a 5 ton 5000kg x 9.81 equals 49050 N pipe along 10 sets of idle pipe conveyor systems i assume it is less than the total normal force?
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What is 5000 LBS in kilograms?

2 267.96185 kilograms ==


A 9000kg raiload car movin at 3ms strike a stationary not moving 5000kg railroad car what is the kinetic energy of the 9000kg railroad car before the collision?

It is 40500J.


A 9000kg raiload car movin at 3ms strike a stationary not moving 5000kg railroad car. If the two railroad cars couple and move off togetherafter the collision what is there velocity?

1.93 m/s


What is the density of an object has a mass of 20 grams and a volume of 100 cubic centimeter?

Density = (mass) / (volume) = 20/4 = 5 grams per cc


What is the velocity of a 9000 kg railroad car and a 5000 kg railroad car when the first car was traveling at 3 m per s?

Momentum is mass multiplied by velocity. The formula for momentum is: p (momentum)= m (kg ) x v (meters/second). So in this case, the mass is 9000 kg and the velocity is 3 m/s, so its momentum is 27000 kg-m/s, or N-s.