Need moles NaCl first.
17.52 grams NaCl (1 mole NaCl/58.44 grams)
= 0.29979 moles NaCl
=====================Now.
Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters )
Molarity = 0.29979 mole NaCl/2 Liters
= 0.1499 M NaCl
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Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
Molarity = moles of solute/volume of solution 2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters = 0.132 Molarity of NaOH
4.00 grams of NaOH have been added to 2.00 liters of water. The molarity of this solution is?
- measuring the mass of this compound and the volume (or mass) of the solution - by chemical analysis (and determination of the concentration of this compound) If you know the molarity, multiply moles by molecular weight and adjust per the volume you have. If you don't know the molarity, a simple means is to just evaporate the solvent and weigh the remaining compound
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Molarity = moles of solute/volume of solution so, 29.4 grams sounds about right.
The molarity is 2,973.
This molarity is 0,5.
If 1,1 is grams the molarity is 0,317.