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A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Wiki User
∙ 13y ago
Molarity = moles of solute(CuSO4)/volume of solution(Liters)
0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4
Molarity = 0.00606 moles/0.020 liters
= 0.303 Molarity
Wiki User
∙ 13y ago
First, calculate the moles of CuSO4 in the residue using its molar mass. Then, using the volume of the original solution, calculate the molarity by dividing the moles by the volume in liters (20.0 mL converted to liters). This will give you the molarity of the original CuSO4 solution.
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When 125 grams of solution was evaporated to dryness. 14.3 grams of solute was recovered what was the percentage of the solute?
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What is the abstract noun for dry?
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