i am not sure but i can give u the expression for the speed at periapsis, Vp2 = 2μ{ 1/r1 - 1/(r1+ r2 )}.
To calculate the periapsis, you need to know the initial velocity and distance relative to a central body. The periapsis is the point of closest distance in an orbit. One way to calculate it is by using the specific orbital energy equation, which is the sum of the gravitational potential energy and the kinetic energy: ε = -(GM) / (2a), where ε is the specific orbital energy, G is the gravitational constant, M is the mass of the central body, and a is the semi-major axis of the orbit. The periapsis can then be determined by subtracting the distance relative to the central body from the semi-major axis.
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
v=d/t where d is the distance and t is the time
Work is not defined as distance/time, but rather: work= force x distance Distance divided by time will give you velocity. Displacement (or distance traveled) = velocity x time
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
Add the rivers velocity to the boats velocity
Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.
yes...
More information is needed.
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
Speed and Velocity are two different things . Velocity- "the rate at which an object changes its position." Speed- "How fast an object is moving". To calculate speed and velocity, you first need to calculate distance and time. Velocity is considered to be a more logical term
You calculate the charge in velocity, not in distance.
I assume you refer to the formula distance = velocity x time. If an object moves upward, the distance would become the height.
The velocity of a boat relative to the shore is also known as 'Speed over ground' can be established by two main methods.1. Speed over ground can be established as average speed over ground, by making two position fixes in the chart, using the compass bearings towards at least two shore objects in each of the fixes and writing down the time. The average speedAvSpeed = Distance covered (measured in the chart) / Time elapsed between the two fixes.A fix is a determination of the boat position using landmarks shown in the chart.2. Using a GPS (Global Positioning System). A modern GPS gives you the instant speed over the ground. Using the distance travelled (registered by the GPS) and the elapsed time (also recorded by the GPS) you can calculate the average speed over ground (average velocity relative to shore). Some GPS units can calculate this average speed, if you reset the distance travelled and time elapsed data on the GPS when you start your navigation.
No. That's only one of several possibilities. -- with initial velocity, distance, and time, you can calculate acceleration -- with final velocity, distance, and time, you can calculate acceleration -- with force and mass, you can calculate acceleration -- with initial and final momentum, you can calculate acceleration -- with initial and final kinetic energy, you can calculate acceleration -- with mass, velocity at either end, and kinetic energy at the other end, you can calculate acceleration And I'm sure there are several more that I've missed.
The distance travelled, and the time taken.
The product of velocity and time yields distance travelled if the velocity is constant for the time in question. If velocity is not constant, one must first calculate the average velocity over a given time period before multiplying it by the time involved.