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Length X Width X Depth = volume
There are several methods that can be used to calculate the density of a metal ball. The density of a metal ball can be derived from the fact that the volume is: 4*(pi)*r^3/3 and the denisty is mass/volume. If the mass and moment of inertia are known but the dimensions of the metal ball are not, then you can use the fact that the moment of inertia of the ball is 2m*r^2/5 and solve for m to get r=(5I/2)^.5 and plug in the value for r into the volume equation then calculate the density of the ball by dividing the mass by the calculated volume.
A ball is a spherical shape and the formula for finding the volume of a sphere is: Volume = 4/3 x pi x radius3 Diameter of the ball = 9 and 9/16 inches so the radius will be half of this which is 4.78125 inches. Volume = 4/3 x pi x 4.781253 = 457.8391924 cubic inches. Therefore the volume of air in the ball is 458 cubic inches correct to three significant figures.
It is not possible to calculate the area given only the volume.
You cannot calculate volume of surface area. If you meant 20m3, then the volume would be 20,000 litres.
To calculate the weight of a given amount of steel in the metric system you simply multiply the volume of steel in cubic meters times the SG of steel (typically 7.85 but it varies slightly depending on the type of steel). The answer will be in metric tonnes or MT.
the volume of a steel sheet plate is < length *breath *height >
Density = mass/volume let us say the mass of the steel ball and the ship are same. but the steel ball is fully enclosed, a tight spherical volume, where as the ship is a hollow, occupies more volume (multiple times) as that of the spherical ball. Considering the first equation, u know well the density of steel ball is much higher than the steel ship.
Same way you always calculate volume. The material makes no difference the shape is what's important.
Length X Width X Depth = volume
Ignore the zinc content. Just calculate the volume of steel in the given type (e.g schedule 40), size and length of pipe and multiply by the density of that grade of steel.
You can solve this in two steps. (1) Calculate the ball's volume. Use the formula for a sphere, and remember that the radius is 1/2 the diameter. Convert the result it either to cubic decimeters (= liters) or to cubic meters. (2) Divide the mass by the volume.
There are several methods that can be used to calculate the density of a metal ball. The density of a metal ball can be derived from the fact that the volume is: 4*(pi)*r^3/3 and the denisty is mass/volume. If the mass and moment of inertia are known but the dimensions of the metal ball are not, then you can use the fact that the moment of inertia of the ball is 2m*r^2/5 and solve for m to get r=(5I/2)^.5 and plug in the value for r into the volume equation then calculate the density of the ball by dividing the mass by the calculated volume.
For an object to flat it must displace more water than it weighs. So a 1 kg hollow steel ball bust displace 1kg of water. 1 kg of water has a volume of 1 litre so the steel ball must have a volume greater than 1l. Note: 1lite = 1000cm^3
1.3 cm3
Unless you can calculate or measure the volume, you cannot. And even if you could you would get the average density - of the material of the ball and the air inside.
cubic metres