V=(L)(pi)(r)^2
L is length (ex: water occupies 9 m of a 10 m tube, i think meters is correct)
r is radius of tube
note: (pi)(r)^2 = area of a circle
Measure the outer diameter of the tube and its' length. Calculate each tube volume and multiply by number of tubes. For those who want to calculate the inside liquid capacity of the shell side, it is advise to include the baffle volume with the tube bundle volume.
7.6 ml
The volume of water displaced is equal to the volume of the object submerged into the water
Subtract what is left from the original volume.
Volume of a cylinder (the test tube) = pi*radius2*height or length Volume = pi*15.52*204 = 49011*pi cubic mm
The easy way: Pour the water into a graduated container, like a graduated cylinder, and read the volume directly. The hard way: Calculate the volume of a regularly shaped container (cylindrical or rectangular). Pour the water into the container. Measure the height of the water in the container. Calculate the volume of the unfilled portion of the container. Subtract this volume from the total volume of the container.
calculate the volume of water a drum can take the drum is 72inch diameter by60inch height
you subtract the weight of the water from the weight of the measuring cylinder and you get the volume of the stone
water displacement
To calculate volume of water for hydro test you need to use the formula pi times radius (squared) times length. Pi is equal to 3.14.
Divide its weight by 20736 cubic units of volume.
To calculate the volume of an irregular object you will need a container with meaurements and water. Place the irregular object in your container and fill with water until the entire object is covered. Record volume A. Then remove the irregular object and record volume B. The volume of your irregulare object is equal to volume A minus volume B.