No
No. It may change its weight if weighed at varying depths.
Suppose Y is a variable which is dependent on another variable X. Then the units used for the rate of change in Y, with respect to X, will be the units of Y divided by the units of X. For example, if x is the length of a side of a cube (in cm), and Y is its volume (in cm3), then the rate of change of Y, with respect to X, is measures in cm3/cm.
density = mass / volume = 13 g / 5 cm3 = 2.6 g/cm3
The density of the 6 cm3 block of ice is approximately 0.67 grams/cm3. This can be calculated by dividing the mass (4 grams) by the volume (6 cm3).
1 cm3 = 1 mL 275 cm3 = 275 mL
No
No. It may change its weight if weighed at varying depths.
The formula is: cm3 x 0.000264 = US gallons.
1 cm3 is 0.001liters.
12 cm3 (because 1 cm3 equals 1 milliliter
•Serpentinization accompanied by: -Redox and H2 generation -Volumetric change •3.3 g/cm3 •2.7 g/cm3 -Heat generation
(50g)/(15g/cm3)=3.333...cm3 or 3 1/3 cm3
548.6 cm3
Cubic centimetres and millilitres are equal measurements for volume. Therefore, no real conversion is necessary; all you have to do is change the unit: 1 cm3 = 1 mL 563 cm3 = 563 mL
The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7The answer is 1 cm3/(1.5 m3) = 1 cm3/150 cm3 = 1/(150)3 = 1/3375000 = 2.962962...*10-7
With a density of about 1.33 g/cm3 Jupiter's density can be compared to: * Glucose 1.350 g/cm3 * Fluorine refrigerant R-12 1.311 g/cm3 * Dichloromethane 1.326 g/cm3 * Dichlorobenzen 1.301 g/cm3 * Mylar 1.39 g/cm3 * Gravel 1.362 g/cm3 * Maple Syrup 1.362 g/cm3