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Q: Find three consecutive numbers where the product of the smaller two numbers is 40 less than the square of the largest number?

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Related questions

Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

5,6,7

11,12,13

8,10,12

4, 6, and 8

3, 5, 7

8, 9, and 10

1, 3, 5

16, 17 and 18

14, 15, 16

5, 6 and 7

4, 6, and 8

8, 10, 12

3, 5, 7

5, 6, 7

4,6,8

I hope you meant "product of smaller two"! 5 x 6 = 30, 72 = 49

Five, six and seven. (Check the math, so you can be sure!)

the answer is 6

The three numbers are 6, 8, and 10. 102 - 8 x 6 = 52

This isn't possible. They'd have to be even (8, 10, 12).

The three numbers are 10, 9, and 8: 102 - (9 x 8) = 28

The product of 2 consecutive positive number is 48. Find the 2 numbers

The three numbers are 3, 5 and 7. 72 - (5 x 3) = 49 - 15 = 34

4,6,8,10