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Slope intercept form: y = mx + c where m and c are constants.

Subtract y from both sides: 0 = mx + c -y

Rearrange: 0 = mx - y + c = standard form.

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Q: How do you change slope intercept to standard form?
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What is the standard form for a slope intercept?

y=mx+b. Standard form is Ax+By=C. To get to standard form from slope intercept, Move slope times x over to the y side and change the positive or negative sign.

How do you change from standard form to slope intercept?

Solve the standard form for the dependent variable, commonly 'y'.

Who do you change from slope intercept form to standard form?

This is stupid! Why do you even need m help?!

Is 2x equals 7 in standard form or slope-intercept form?

Standard. You need a linear equation in two variables for slope-intercept form.

What is the difference between the slope intercept form and the standard form?

Slope intercept form is displayed as y=mx+b.

What is the standard form of a slope?

In the standard form of a linear equation:y = mx + bm is the slope* * * * *The above is the slope-intercept form, not the standard form, which isax + by + c = 0The standard form can be converted to the slope intercept form by rearranging, as follows:by = -ax - cso y = -(a/b)x -(c/b)And then, the slope (or gradient) is (-a/b).

What does slope intercept look like?

The standard form of the slope-intercept equation is: y = mx + b where "m" is the slope, and "b" is the y-intercept.

What is the equation of a line in standard form?

The standard form equation of a line is y=mx+b. M represents the slope; slope is the change in x over the change in y. B represents the y-intercept.

How do you transform the standard form of the linear function into slope intercept form?

ax+by=c --- standard form and slope intercept form is y=mx+b,, so for example: 8x+4y=16 ----this in its standard form so if we change it to slope intercept form, we transpose 8x beside 16.. there fore, the result is 4y=-8x+16. .however.. in slope intercept form,, the variable y should not have any coeffiecient.. so we should dived 4y, -8x and 16 by 4,, therefore the result is y=-2x+4.. so the slope intercept form of 8x+4y=16 is y=-2x+4

Can a linear equation be graphed with only the slope and intercept when it is in standard form?

That's all you need to know in order to draw the graph. Note that it doesn't matter what form the equation is written in. The form of presentation doesn't change the slope or intercept.

What is the slope for the graph of 4x plus 9?

Slope = 4.In standard slope-intercept form y = mx + b, with m = slope and b = y-intercept.

How do you find the slope and y-intercept for y equals 2x-10?