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Slope intercept form: y = mx + c where m and c are constants.

Subtract y from both sides: 0 = mx + c -y

Rearrange: 0 = mx - y + c = standard form.

Q: How do you change slope intercept to standard form?

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y=mx+b. Standard form is Ax+By=C. To get to standard form from slope intercept, Move slope times x over to the y side and change the positive or negative sign.

Standard. You need a linear equation in two variables for slope-intercept form.

In the standard form of a linear equation:y = mx + bm is the slope* * * * *The above is the slope-intercept form, not the standard form, which isax + by + c = 0The standard form can be converted to the slope intercept form by rearranging, as follows:by = -ax - cso y = -(a/b)x -(c/b)And then, the slope (or gradient) is (-a/b).

The standard form of the slope-intercept equation is: y = mx + b where "m" is the slope, and "b" is the y-intercept.

The standard form equation of a line is y=mx+b. M represents the slope; slope is the change in x over the change in y. B represents the y-intercept.

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y=mx+b. Standard form is Ax+By=C. To get to standard form from slope intercept, Move slope times x over to the y side and change the positive or negative sign.

Solve the standard form for the dependent variable, commonly 'y'.

This is stupid! Why do you even need m help?!

Standard. You need a linear equation in two variables for slope-intercept form.

Slope intercept form is displayed as y=mx+b.

In the standard form of a linear equation:y = mx + bm is the slope* * * * *The above is the slope-intercept form, not the standard form, which isax + by + c = 0The standard form can be converted to the slope intercept form by rearranging, as follows:by = -ax - cso y = -(a/b)x -(c/b)And then, the slope (or gradient) is (-a/b).

The standard form of the slope-intercept equation is: y = mx + b where "m" is the slope, and "b" is the y-intercept.

The standard form equation of a line is y=mx+b. M represents the slope; slope is the change in x over the change in y. B represents the y-intercept.

ax+by=c --- standard form and slope intercept form is y=mx+b,, so for example: 8x+4y=16 ----this in its standard form so if we change it to slope intercept form, we transpose 8x beside 16.. there fore, the result is 4y=-8x+16. .however.. in slope intercept form,, the variable y should not have any coeffiecient.. so we should dived 4y, -8x and 16 by 4,, therefore the result is y=-2x+4.. so the slope intercept form of 8x+4y=16 is y=-2x+4

That's all you need to know in order to draw the graph. Note that it doesn't matter what form the equation is written in. The form of presentation doesn't change the slope or intercept.

Slope = 4.In standard slope-intercept form y = mx + b, with m = slope and b = y-intercept.

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