This is the equation of a straight line, and the form it's in is what they call the "standard form",
where the slope and intercept of the line are as plain as my nose.
The standard form is:
Y = (this number is the slope) X +(this number is the y-intercept)
In the equation given, y = 2x - 10 ,
slope = 2
y-intercept = -10
How can you use 2x10 to find 4x10
8x10
Divide 2 the 2 from the 2xfrom both sides, subtract the 5 and there is your answer.
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
The slope can be a fraction.
The slope is -5
2/5 is the slope
the slope is 0
How can you use 2x10 to find 4x10
That's a vertical line; the slope is not defined.
7
The equation for the slope of a line is y=mx+b
Invalid question. You cannot find the slope with just y=-12.
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
slope = 31 and intercept = 4
-36
slope = -4 for y=mx+c, slope=m, y intercept=c