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Q: How do you completely factor x to the fourth power minus y to the fourth power?

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(x2 - 2)(x2 + 2)

(x2 + 1)(x2 - 2)

2x to the fourth power minus 162 equals -146

x^2(x - 4)(x + 4)

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x cubed minus 216

1x to the power of 4

3x^3(x - 4)

(3x^2 - 4y^2)(3x^2 + 4y^2)

4(10x4 + 3)(10x4 - 3)

6(x + 9)(x - 1)

There is a formula for the "difference of squares." In this case, the answer is (x2 - 5)(x2 + 5)

So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).

-16,128

(x4 - 16) = (x2 + 4) (x2 - 4) = (x2 + 4) (x + 2) (x - 2)

It is +1

which of the following is a factor of x2 - 5x - 6

Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).

3x^4 - 12 = 3(x^4 - 4) = 3(x² + 2)(x² - 2)

(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)

91,000,000

You start by using the difference of squares: x24 - 1 = (x12 + 1)(x12 - 1) The second term is again a difference of squares, so you can apply this special factoring once again.

its easy just maximize the four into the irregular eight that in thus giving it nine that is only in mathematical terms people

5x^2(4x - 5)(5x + 11)

23