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what you do is separate the sizes into a 9 x 18 rectangle which gives you a total of 162 square feet. and then the remaining triangle can be worked using 1/2B x H which is 3.5 x 18 = 63 square feet.

<P>Add the two totals together and therefore 162 + 63 = 225 square feet.

The assumption is made that a perimeter of 9 + 16 + 18 + 21 can be formed by a rectangle and one right triangle (1/2 x B x H). This is not so--try it! You cannot connect the hypotenuse of the triangle if you use the form suggested. 7^2 + 18^2 does not equal 21^2!

This answer can be determined using the law of cosines. As long as you know two sides and one angle--OR three sides--it can be solved. One length is 21, one length is 9, the third length is 24.1 (sqrt of 16^2 + 18^2).

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