43 5 378 -4393
H2o2
The molar mass of hydrogen is approximately 1.008 g/mol. To convert this to kilograms, we divide by 1000 to get 0.001008 kg/mol.
To convert from mol percent to weight percent, we need to know the molecular weights of the substances involved. Without this information, we cannot accurately convert 0.0141 mol percent to weight percent.
To find the percent composition of hydrogen in NH4HCO3, we first calculate the molar mass of the compound. NH4HCO3 has a molar mass of 79.06 g/mol. The molar mass contribution of hydrogen is 1.01 g/mol. To find the percent composition of hydrogen, we divide the molar mass contribution of hydrogen by the molar mass of NH4HCO3 and multiply by 100: (1.01 g/mol / 79.06 g/mol) x 100 ≈ 1.28%.
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
The molar mass of butane (C4H10) is 58.12 g/mol. The molar mass of hydrogen in butane is 10.81 g/mol. To calculate the mass percent of hydrogen in butane, you would divide the molar mass of hydrogen by the molar mass of butane and multiply by 100. This gives you a mass percent of approximately 18.6%.
The molar mass of carbon is 12 g/mol and hydrogen is 1 g/mol. Therefore, the total mass of 1.2 moles of carbon is 1.2 mol * 12 g/mol = 14.4 g, and the total mass of 3.2 moles of hydrogen is 3.2 mol * 1 g/mol = 3.2 g. The percent composition by mass is then (14.4 g carbon / (14.4 g carbon + 3.2 g hydrogen)) * 100% = 81.8% carbon and (3.2 g hydrogen / (14.4 g carbon + 3.2 g hydrogen)) * 100% = 18.2% hydrogen.
The percent composition of CH3CH2OH (ethanol) is as follows: Carbon (C): (2 * 12.01 g/mol) / 46.07 g/mol x 100 = 52.20% Hydrogen (H): (6 * 1.01 g/mol) / 46.07 g/mol x 100 = 13.09% Oxygen (O): 16.00 g/mol / 46.07 g/mol x 100 = 34.71% Therefore, ethanol is composed of 52.20% carbon, 13.09% hydrogen, and 34.71% oxygen.
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
The mass percent of hydrogen in hydrogen peroxide (H2O2) is 5.88%. This is calculated by taking the total mass of hydrogen in one molecule of H2O2 (2.01 g) divided by the total molar mass of H2O2 (34.02 g/mol) and multiplying by 100.
To find the percent by mass of hydrogen in C7H8, we first calculate the molar mass of C7H8: (712.0107) + (81.00794) = 92.08958 g/mol. Next, we find the mass contribution of hydrogen: 8*1.00794 = 8.06352 g/mol. Finally, the percent by mass of hydrogen is (8.06352/92.08958) * 100 ≈ 8.75%.
To find the number of moles of hydrogen gas, we first need to convert the mass of hydrogen gas from grams to moles using the molar mass of hydrogen gas (2 g/mol). 5.04 grams of hydrogen gas is equal to 5.04 g / 2 g/mol = 2.52 moles of hydrogen gas.