43 5 378 -4393
H2o2
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
Assuming you mean liberated, none. Magnesium does not contain hydrogen.
4,51 moles hydrogen exist.
The formula for water is H2O: Molar mass = 18.02 g / mol H2OIn one mole of H2O there are 2 mol H and 1 mol O:2 mol H1.010 g H = 2.020 g H1 mol H1 mol O16.00 g O = 16.00 g O1 mol OThe percentage of each element is calculated from the quantities in 1 mole as:% element = g element 100g H2O% H...=...2.020 g H... 100......=...11.21 % H18.02g H2O% O...=...16.00 g O... 100......=...88.79 % O18.02g H2ONote: 11.21 + 88.79 = 100.00
0.63 mol of (NH4)2SO4 contain 3,978.10e23 hydrogen atoms.
First assume you have 100 g of the substance & then convert to moles using the molecular weight of each element:Na: 32.39 g / (22.99 g/mol) = 1.409 mol NaS : 22.53 g / (32.07 g/mol) = 0.703 mol SO : 45.07 g / (16.00 g/mol) = 2.817 mol ONext divide each mole amount by the smallest one of the group, in this case sulfur. This gives you the ratio of each element in the compound.Na: 1.409 mol / 0.703 mol = 2.00S : 0.703 mol/0.703 mol = 1.00O: 2.817 mol/0.703 mol = 4.01Round to the nearest whole number & you get the formula: Na2SO4 (sodium sulfate)
9H2 + 3N2 ------> 6NH3 3 moles of N2 would be required.
No. Hydrogen is H (14 g/mol) and Water is H2O (14x2+16 so 44 g/mol).
Carbon (C) has a atomic weight of 12 gr/mol Hydrogen (H) has an atomic weight of 1 gr/mol Therefore C2H4 has a molecular weight of 28 gr/mol (2x12 + 4x1) By dividing 86.2 grams by 28 gr/mol, you get 3.59 moles.
7.4 mol of H2
The conversion. 4 mol C5H10 ( 10 mol H/1 mol C5H10 ) = 40 mol Hydrogen.