You need to know the linear density.
Multiply gpm by the number of minutes the flow lasted, to find the gallons of volume that flowed during that time.
Multiply your gpm by 60.
8 GPM
0.1gpm/sq-ft
Kw x 3412 / 10000 = gpm I think
You need to know the linear density.
Multiply gpm by the number of minutes the flow lasted, to find the gallons of volume that flowed during that time.
1TR= 12mbh 1gpm= 2.4tr 1gpm=28.8mbh
Multiply your gpm by 60.
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First you need the size of the pipe and the volume of water supply. Pressure will vary during usage. Standard well system operates between 20-40 psi and city systems operate from 50-70 psi.
A fixture unit is 1 cubic foot of water (7.48 gallons) If your using pumped drainage /soil system then for every GPM of flow rate one has to consider it as ONE FU
52 gpm
gallon per minute (gpm).
7.48 Gal (1 CU FT) = 1 FU Or 1 GPM of pumped drainage = 1 FU The above equation that was submitted makes no sense whatsoever. Conversion of Fixture Units to gpm is non-linear; gpm per FU decreases as the total number of FU increases. I am a civil engineer, not mechanical engineer, but I know there are resources available either through International or local building codes that guide the designer.
2650 gph = 44.167 gpm