16.387 cc is equal to one cubic inch of water or anything else.
You multiply the height of the column by the surface area of the base.
The inch is a measure of distance and the cubic inch is a measure of volume. You cannot convert one to the other.
A gallon is a unit of volume, an acre is a unit of area, so you can't really convert that. If you know that the acre is covered with water to a certain depth - say, half an inch - then you would have a volume.
The question as posed is unanswerable. In order to compute the weight of an inch of water, one would have to know the volume, or area the one inch covers. (ie., a square foot of water one inch deep would weigh=X)
A cubic foot is a unit of volume. An inch is a unit of length. Therefore, the two units are incompatible.
It takes 24.50985 feet of 1 inch pipe to hold one gallon of water. Jeff Payne jpayne@texwipe.com
-- 1 square inch weighs nothing, since its volume is zero. -- If the square inch is one end of a vertical column of water, then the column weighs about [ 5pounds 31/3ounces ] for each 12-ft of its height.
this question can't be answered because you can only get a surface area calculation from 30X42 inches, (which is 1260 square inches) To calculate the volume, you need the depth of the water as well.
inch = length, ml = volume- there is no conversion between them
27.71 inches of water column equals 1 psi
The inch is a measure of distance and the cubic inch is a measure of volume. You cannot convert one to the other.
None. A square inch has no volume.
A gallon is a unit of volume, an acre is a unit of area, so you can't really convert that. If you know that the acre is covered with water to a certain depth - say, half an inch - then you would have a volume.
The volume of water in a 4-inch diameter, 1-foot section of pipe is 0.6528 gallons of water.
1.15 gallons of water.
It is approx 46.3 feet.
An inch is a unit of length and a cubic inch is a unit of volume. One does not convert into the other.
A cubic inch is a unit of volume. An inch is a unit of length. The two units are therefore incompatible.