impossible because of the 2 then K. It has to be k2 for it to be possible.
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
The applicable rules of thumb are: All common nitrates are soluble. All common alkali metal salts are soluble. Applying those two rules, the only thing we're left with is silver chloride, which is insoluble. In fact, the solubility rule for chlorides is "All common chlorides are soluble except silver, mercury (I), and lead."
0grams
Pb(NO3)2 is lead II nitrate. It used to be used to make the color in paint, but it's toxic.
43.28 M
I think.... Pb(NO3)2 + Na2S -> PbS + 2(NaNO3) If someone knows for sure please kill my answer.
Pb(No3)2(aq) + KI(aq) --> PbI2(s) + KNO3(aq) aq = aqueous s = solid Lead iodide is a yellow precipitate!
White precipitates of Lead chloride (PbCl2) are formed because the solubility product (KSP) of Lead chloride is very low.
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
CaSO4 + Pb(NO3)2 = Ca(NO3)2 + PbSO4But since Pb is less reactive than Ca according to the reactivity series, Pb can not replace the Ca in CaSO4. Therefore, the reaction will not occur.
The applicable rules of thumb are: All common nitrates are soluble. All common alkali metal salts are soluble. Applying those two rules, the only thing we're left with is silver chloride, which is insoluble. In fact, the solubility rule for chlorides is "All common chlorides are soluble except silver, mercury (I), and lead."