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How do you convert cm length x width x height into inches?
There are 2.54 cm/inch; so to convert cm to inches, divide by 2.54. It is the same whether the measurement is length, width, or height.
How do you convert 156 cm for baggage?
Length + Width + Height must not be greater than 156 cm
Width of this page mm or cm?
what is the width of a page in mm or cm
The width of a rectangle is 2 cm less than 7 times the lenght the perimeter is 60 cm find the width and length?
The length is 4 cm, the width is 26 cm.
What is the width of a rectangle with length 14 cm in an area of 161 cm²?
Its width is: 161/14 = 11.5 cm
How do you convert cm length x width x height into inches?
There are 2.54 cm/inch; so to convert cm to inches, divide by 2.54. It is the same whether the measurement is length, width, or height.
How do you convert 156 cm for baggage?
Length + Width + Height must not be greater than 156 cm
How do you convert 158 cm into inches for luggage requirements of height width and length?
2.54 cm = 1 inch. Divide 158 by 2.54 to convert to inches (158 ÷ 2.54 = 62.2 inches)
Width of this page mm or cm?
what is the width of a page in mm or cm
The width of a rectangle is 2 cm less than 7 times the lenght the perimeter is 60 cm find the width and length?
The length is 4 cm, the width is 26 cm.
A rectangle has a length of 17.62cm width of 13.7cm Find the area in feet?
First convert the dimensions to ft: 17.62 cm = 17.62 cm * (1 in/2.54 cm) * (1 ft/12 in) = .5781 ft 13.7 cm = 13.7 cm * (1 in/2.54 cm) * (1 ft/12 in) = .449 ft Area = length * width = .5781*.449 = .260 ft^2
What is the width of a rectangle with length 14 cm in an area of 161 cm²?
Its width is: 161/14 = 11.5 cm
If the length of a rectangle is 3 cm longer than twice the width and that the perimeter of the rectangle is 90 cm then what is the width and the length?
the width equals 14 cm. and the length equals 31 cm.
What is the width of a rectangle with an area of 34cm2 and length of 9 cm?
Area = length x width ⇒ width = Area ÷ length = 34 cm2 ÷ 9 cm = 37/9 cm ~= 3.78 cm
What is the perimeter of a rectangle which has a diagonal of 8.50 cm and an area of 3000 square mm showing work with answer?
Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.
What is the area of a rectangle with the length of 45 cm and a width of 30 cm?
The area of a rectangle is: length * width= 45 cm * 30 cm = 1350 cm^2
What is the area of a rectangle with a perimeter of 16cm?
Any area you want greater than 0 cm2 and less than or equal to 16 cm2. perimeter_of_rectangle = 2 x (width + length) 16 cm = 2 x (width + length) ⇒ width + length = 8 cm ⇒ length = 8 cm - width Neither dimension can be negative, so they are both greater than 0 cm and less than 8 cm. Area_of_rectangle = width x length ⇒ area = width x (8 cm - width) = 8 x width - width2 cm2 This has a minimum value when width = 0 cm or 8cm of 0 cm2, so the area of the perimeter must be greater than 0 cm2 (as the width can be neither 0 cm nor 8 cm). This has a maximum value when width = 4 cm: max_area = 8 x 4 - 42 cm2 = 16 cm2. when the width is between 0 cm and 4 cm (and so the length is between 8 cm and 4 cm) the area is between 0 cm2 and 16 cm2 When the width = 4 cm, the length is also 4 cm, that is the rectangle is a square.
