NO
There is no quadratic equation that is 'linear'. There are linear equations and quadratic equations. Linear equations are equations in which the degree of the variable is 1, and quadratic equations are those equations in which the degree of the variable is 2.
Linear Equations are equations with variable with power 1 for eg: 5x + 7 = 0 Simultaneous Equations are two equations with more than one variable so that solving them simultaneously
Linear equations have a variable only to the first degree(something to the power of 1). For example: 2x + 1 = 5 , 4y - 95 = 3y are linear equations. Non-linear equation have a variable that has a second degree or greater. For example: x2 + 3 = 19, 3x3 - 10 = 14 are non-linear equations.
You select the linear combination of the equations in such a way that at each stage you eliminate one variable.You select the linear combination of the equations in such a way that at each stage you eliminate one variable.You select the linear combination of the equations in such a way that at each stage you eliminate one variable.You select the linear combination of the equations in such a way that at each stage you eliminate one variable.
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Equations can be classified according to the highest power of the variable. Since the highest power of the variable in a linear equation is one, it is also called a first-order equation.
The word linear means in a straight line. If the graph is a line, it is linear. Also, linear equations are of the first order; they contain a variable but not a square (or higher power) of a variable. If the equation contains x2 it is not linear.
All equations for which the greatest power of its variable is 1, and that have no absolute value signs surrounding the variable, is linear. Therefore, yes, your problem is linear.
It is called solving by elimination.
true
true
Because linear equations are based on algebra equal to each other whereas literal equations are based on solving for one variable.