mass moment of inertia for a solid sphere:
I = (2 /5) * mass * radius2
(mass in kg, radius in metres)
the moment of inertia of a solid cylinder about an axis passing through its COM and parallel to its length is mr2/2 where r is the radius.
A sphere is a geometric solid because it has 3 dimentions.
A sphere is a solid with no edges.
Sphere ,because the sphere is roll if you put sphere in the table it can be roll. *_*
sphere
The moment of inertia of a solid sphere is given by the formula (2/5) m r2, where m is the mass of the sphere and r is the radius of the sphere.
The formula for calculating the moment of inertia of a solid sphere is (2/5) m r2, where m is the mass of the sphere and r is the radius of the sphere.
The moment of inertia of a solid sphere is derived by integrating the mass of the sphere over its volume, taking into account the distance of each mass element from the axis of rotation. This integration results in the formula for the moment of inertia of a solid sphere, which is (2/5) mass radius2.
The moment of inertia of a solid sphere about its diameter is (2/5)MR^2, where M is the mass of the sphere and R is the radius. This can be derived from the formula for the moment of inertia of a solid sphere about its center, which is (2/5)MR^2, by applying the parallel axis theorem.
The solid disk has a greater moment of inertia than the solid sphere because the mass of the disk is distributed farther from the axis of rotation, resulting in a larger rotational inertia. This difference can be explained by the parallel axis theorem, which states that the moment of inertia of an object can be calculated by adding the moment of inertia of the object's center of mass and the product of the mass and the square of the distance between the center of mass and the axis of rotation.
To derive the moment of inertia of a solid sphere using calculus, you would start by considering a small element of the sphere with volume dV at a distance r from the axis of rotation. Express the mass of this element as dm, then integrate to find the moment of inertia I by summing up the contributions from all such elements. Finally, use the definition of density to express dm in terms of volume element dV, and simplify the integral to obtain the formula for moment of inertia of a solid sphere, which is (2/5)MR^2.
the moment of inertia of a solid cylinder about an axis passing through its COM and parallel to its length is mr2/2 where r is the radius.
The moment of inertia of an object depends on its mass distribution and shape. For simple shapes, such as a point mass or a solid cylinder, mathematical formulas can be used to calculate the moment of inertia. For complex shapes, numerical methods or integration techniques may be necessary to determine the moment of inertia.
The total energy of a rolling solid sphere is the sum of its kinetic energy and its rotational energy. The kinetic energy of the sphere is given by 1/2 * m * v^2, where m is the mass of the sphere and v is its linear velocity. The rotational energy is given by 1/2 * I * w^2, where I is the moment of inertia of the sphere and w is its angular velocity.
Moment of inertia is a measure of an object's resistance to changes in its rotational motion. An example problem illustrating this concept could be calculating the moment of inertia of a solid cylinder rotating around its central axis. The formula for the moment of inertia of a solid cylinder is I (1/2) m r2, where m is the mass of the cylinder and r is the radius. By plugging in the values for mass and radius, you can calculate the moment of inertia of the cylinder.
The moment of inertia of a cylinder is a measure of its resistance to changes in its rotational motion. It depends on the mass distribution of the cylinder and its distance from the axis of rotation. The formula for the moment of inertia of a solid cylinder is 1/2 mass radius2.
The moment of inertia of a solid hemisphere rotating around its axis is given by (2/5) * m * r^2, where m is the mass of the hemisphere and r is the radius.