the moment of inertia of a solid cylinder about an axis passing through its COM and parallel to its length is mr2/2 where r is the radius.
A sphere is a geometric solid because it has 3 dimentions.
A sphere is a solid with no edges.
Sphere ,because the sphere is roll if you put sphere in the table it can be roll. *_*
sphere
The moment of inertia of a solid sphere about its diameter is (2/5)MR^2, where M is the mass of the sphere and R is the radius. This can be derived from the formula for the moment of inertia of a solid sphere about its center, which is (2/5)MR^2, by applying the parallel axis theorem.
To derive the moment of inertia of a solid sphere using calculus, you would start by considering a small element of the sphere with volume dV at a distance r from the axis of rotation. Express the mass of this element as dm, then integrate to find the moment of inertia I by summing up the contributions from all such elements. Finally, use the definition of density to express dm in terms of volume element dV, and simplify the integral to obtain the formula for moment of inertia of a solid sphere, which is (2/5)MR^2.
the moment of inertia of a solid cylinder about an axis passing through its COM and parallel to its length is mr2/2 where r is the radius.
The moment of inertia of an object depends on its mass distribution and shape. For simple shapes, such as a point mass or a solid cylinder, mathematical formulas can be used to calculate the moment of inertia. For complex shapes, numerical methods or integration techniques may be necessary to determine the moment of inertia.
The total energy of a rolling solid sphere is the sum of its kinetic energy and its rotational energy. The kinetic energy of the sphere is given by 1/2 * m * v^2, where m is the mass of the sphere and v is its linear velocity. The rotational energy is given by 1/2 * I * w^2, where I is the moment of inertia of the sphere and w is its angular velocity.
The moment of inertia of a solid hemisphere rotating around its axis is given by (2/5) * m * r^2, where m is the mass of the hemisphere and r is the radius.
The moment of inertia of a solid round shaft is (\frac{π}{32} \times D^4), where D is the diameter of the shaft.
The moment of inertia of a solid disc is smaller than that of a ring because the mass in a disc is distributed closer to the axis of rotation, resulting in less resistance to changes in angular velocity. In a ring, the mass is distributed farther from the axis, increasing the moment of inertia.
Sources of error in the experiment of moment of inertia of a solid cylinder can include friction in the rotating system, inaccuracies in the measuring instruments such as rulers or calipers, variations in the dimensions of the cylinder, and errors in the calculation of the rotational inertia formula. Additionally, external factors like air resistance or vibrations can also introduce errors in the experiment.
Since a sphere is round it is a shape without a face.
Mentioning the axis of a rectangular bar is necessary when calculating the moment of inertia because the moment of inertia depends on the axis chosen. The distance of the axis from the centroid affects the distribution of mass around that axis, which in turn affects the resistance to rotation. Different axes of rotation will yield different moment of inertia values for the same object.
No it is not a solid.