P=5.75. You know 4P is 23 because you subtract 3 from it and are left with 20. Just divide 23 by 4 to get the value of each "p".
P = p + at 82 = 76 + a*20 6 = a*20 6/20 = a that is a = 3/10 or 0.3 That is the answer.
20 equals Y that RVWS
20 = 4p + 5 +p 20 = 5p + 5 5p = 20 - 5 = 15 5p = 15 p = 15/5 = 3
If the probability of a single plug being defective is p then the required probability is 1 - (1- p)4 = 4p - 6p2 + 4p3 - p4
p = 8
P = p + at 82 = 76 + a*20 6 = a*20 6/20 = a that is a = 3/10 or 0.3 That is the answer.
Orbital Shape
orbital shape
20 equals Y that RVWS
It indicates that the Atom's outermost electron is in the 'p' sub shell of electrons It also indicates the element is in the P block of the periodic table
4 and 20 = black birds in a pie.
20 = 4p + 5 +p 20 = 5p + 5 5p = 20 - 5 = 15 5p = 15 p = 15/5 = 3
p = 8. The calculation for this equation works out as follows: 4p - 12 = 20 4p = 20 + 12 4p = 32 p = 32 / 4 p = 8
As is a p block element in period 4 and group 5A, so it has 5 valence (outer) electrons (4s2 4p3).
5p-1=2p-20 3p=21 p=7
p is equal to any number greater than 12. 3p - 16 > 20 3p > 20 + 16 3p > 36 p > 12
If the probability of a single plug being defective is p then the required probability is 1 - (1- p)4 = 4p - 6p2 + 4p3 - p4