P = p + at 82 = 76 + a*20 6 = a*20 6/20 = a that is a = 3/10 or 0.3 That is the answer.
20 equals Y that RVWS
20 = 4p + 5 +p 20 = 5p + 5 5p = 20 - 5 = 15 5p = 15 p = 15/5 = 3
If the probability of a single plug being defective is p then the required probability is 1 - (1- p)4 = 4p - 6p2 + 4p3 - p4
p = 8
P = p + at 82 = 76 + a*20 6 = a*20 6/20 = a that is a = 3/10 or 0.3 That is the answer.
The letter "p" in the symbol 4p3 indicates the variable representing a number that is to be raised to the power of 3.
The letter "p" in the symbol 4p3 indicates the variable or unknown quantity that raised to the power of 3. This means that p is being cubed or multiplied by itself three times.
The electron configuration of arsenic is [Ar] 3d10 4s2 4p3. This means that arsenic has 2 electrons in its outermost shell (4s2 4p3) and belongs to the p-block of the periodic table.
20 equals Y that RVWS
It indicates that the Atom's outermost electron is in the 'p' sub shell of electrons It also indicates the element is in the P block of the periodic table
4 and 20 = black birds in a pie.
20 = 4p + 5 +p 20 = 5p + 5 5p = 20 - 5 = 15 5p = 15 p = 15/5 = 3
p = 8. The calculation for this equation works out as follows: 4p - 12 = 20 4p = 20 + 12 4p = 32 p = 32 / 4 p = 8
5p-1=2p-20 3p=21 p=7
p is equal to any number greater than 12. 3p - 16 > 20 3p > 20 + 16 3p > 36 p > 12
As is a p block element in period 4 and group 5A, so it has 5 valence (outer) electrons (4s2 4p3).