P=5.75. You know 4P is 23 because you subtract 3 from it and are left with 20. Just divide 23 by 4 to get the value of each "p".
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P = p + at 82 = 76 + a*20 6 = a*20 6/20 = a that is a = 3/10 or 0.3 That is the answer.
20 equals Y that RVWS
20 = 4p + 5 +p 20 = 5p + 5 5p = 20 - 5 = 15 5p = 15 p = 15/5 = 3
If the probability of a single plug being defective is p then the required probability is 1 - (1- p)4 = 4p - 6p2 + 4p3 - p4
p = 8