Rem to Find area and rectangle of a rectangle Input "Length?",l Input"Breadth?",b let area=l*b let perimeter=2*l+b ?area ?perimeter
as perimeter =8 so 4l=8 , so l=2. now area= [l][l]=(2)(2)=4
Perimeter l+l+w+w= 70ft Area LxW =300 sqft
A square that measures 4 per side. Perimeter = L + L + L + L = 4L = 4*4 = 16 Area = L * L = 4*4 = 16 Although technically they won't be equal since perimeter has units of length, while area has units of squared length.
Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.
Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.
Perimeter = 4L where L is the length. So in this case L=3 and area is 3x3 or 32 =9 there perimeter can not be 4 because 4x4=16 it is is the square root of 12
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
Perimeter= 2(l+b) =2*39 =78m = Area =l*b = =24*15 =360m
L=PH L=PH Lateral Area= (Perimeter of the base)(the height of the figure)
Area of a rectangle = l x bso, 7x3=21 area=21 perimeter of a rectangle = 2(l+b) 2(7+3) = 2x10 =20 this is your answer by kitty kat amrita
Perimeter = 2 x L + W so L + W = 9, this would be 6 x 3 to give area of 18