Area: Find some of the lengths, then cut the L in half and work it out from there.
Perimeter: Add all the lengths together.
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Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.
Perimeter = 4L where L is the length. So in this case L=3 and area is 3x3 or 32 =9 there perimeter can not be 4 because 4x4=16 it is is the square root of 12
To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.
Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.
Area of a rectangle = l x bso, 7x3=21 area=21 perimeter of a rectangle = 2(l+b) 2(7+3) = 2x10 =20 this is your answer by kitty kat amrita