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What is the perimeter of a square with an area of 144 in2?
Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.
What is the area of a square with a perimeter of 12feet?
Perimeter = 4L where L is the length. So in this case L=3 and area is 3x3 or 32 =9 there perimeter can not be 4 because 4x4=16 it is is the square root of 12
Area 36 and perimeter 40 what are the sides?
To find the sides of a rectangle with an area of 36 and a perimeter of 40, we can use the formulas: area (A) = length (l) × width (w) and perimeter (P) = 2(l + w). From the area equation, we have ( l \times w = 36 ), and from the perimeter equation, ( l + w = 20 ). Solving these equations, we find the dimensions to be ( l = 18 ) and ( w = 2 ), or vice versa. Thus, the sides of the rectangle are 18 and 2.
What is the area of a rectangle with the perimeter of 42.5 cm?
To find the area of a rectangle with a given perimeter, we first use the formula for the perimeter, which is ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Given the perimeter of 42.5 cm, we have ( l + w = 21.25 ) cm. However, without specific values for length and width, we cannot determine the exact area, as it depends on the dimensions chosen. The area can be calculated as ( A = l \times w ), but multiple combinations of ( l ) and ( w ) can yield the same perimeter but different areas.
What does a rectangle with an area of 24 and a perimeter of 22?
To find the dimensions of a rectangle with an area of 24 and a perimeter of 22, we can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and the width be ( w ). From the area, we have ( lw = 24 ), and from the perimeter, ( 2(l + w) = 22 ), simplifying to ( l + w = 11 ). Solving these equations simultaneously, we find the dimensions are ( l = 8 ) and ( w = 3 ) (or vice versa).
What is area of square with perimeter 8?
as perimeter =8 so 4l=8 , so l=2. now area= [l][l]=(2)(2)=4
What is the perimeter and area of a yard that length is 20ft and width is 15ft?
Perimeter l+l+w+w= 70ft Area LxW =300 sqft
Which of the squares has an area that is equal to its perimeter?
A square that measures 4 per side. Perimeter = L + L + L + L = 4L = 4*4 = 16 Area = L * L = 4*4 = 16 Although technically they won't be equal since perimeter has units of length, while area has units of squared length.
How do you simplify an expression for the perimeter and area of a rectangle?
Represent the length of the rectangle by L and the width by W. The perimeter = 2L + 2W = 2(L + W). The area = L x W.
What is the perimeter of a square with an area of 144 in2?
Area = 144 sq inches => Length of side, L = 12 inches => Perimeter = 4*L = 48 inches.
What is the area of a square with a perimeter of 12feet?
Perimeter = 4L where L is the length. So in this case L=3 and area is 3x3 or 32 =9 there perimeter can not be 4 because 4x4=16 it is is the square root of 12
What is the effect on the perimeter of a rectangle if the dimension are doubled what is the effect on its area?
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
Area 36 and perimeter 40 what are the sides?
To find the sides of a rectangle with an area of 36 and a perimeter of 40, we can use the formulas: area (A) = length (l) × width (w) and perimeter (P) = 2(l + w). From the area equation, we have ( l \times w = 36 ), and from the perimeter equation, ( l + w = 20 ). Solving these equations, we find the dimensions to be ( l = 18 ) and ( w = 2 ), or vice versa. Thus, the sides of the rectangle are 18 and 2.
What does a rectangle with an area of 24 and a perimeter of 22?
To find the dimensions of a rectangle with an area of 24 and a perimeter of 22, we can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and the width be ( w ). From the area, we have ( lw = 24 ), and from the perimeter, ( 2(l + w) = 22 ), simplifying to ( l + w = 11 ). Solving these equations simultaneously, we find the dimensions are ( l = 8 ) and ( w = 3 ) (or vice versa).
Perimeter and area of a rectangle with a length of 24 m and width of 15 m?
Perimeter= 2(l+b) =2*39 =78m = Area =l*b = =24*15 =360m
How do you draw a shape with the same area and perimeter?
To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.
How do you find the length and wide of an area if you know the perimeter and an area?
Perimeter = 2*L + 2*W Area = L*W L = Area / W Perimeter = 2*Area / W + 2*W W * Perimeter = 2*Area + 2*W^2 Let A=area, and P= perimeter. 0=2W^2-PW+2A Quadratic formula: W= (P + root(P^2-16A))/4 or W= (P - root(P^2-16A))/4 Once you have W, L is simply A/W. Have fun, and maybe include some numbers to work with next time.
