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It would be impossible. A trapezoid can't have three right angles. It would just make a rectangle.
Draw a square
Draw a parallelagram this has the opposite sides parallel and no right angles
Yes, as long as they all add up to 180 degrees. A triangle cannot have 2 right angles. A triangle with three different angles is called a scalene triangle.
draw four lines the make 3 right angles but don't connect at the end continue to finish the pentagon with whatever lines you want
no
It is impossible to have a triangle with 3 right angles. It is possible to draw a triangle with three right angles on the surface of a sphere: www.metacafe.com/watch/769025/270_degree_triangle_yes_3_right_angles
Yes.
The sum of all four angles is 360 degrees. If three of the angles were right angles then the fourth would have to be a right angle. You would then have a rectangle or a square, but not a trapezium.
No, because then it would be a rectangle.
The sum of the interior angles of a quadrilateral is 360 degrees. If three of the angles are right angles, that is, of 90 degrees each, the the fourth must be 90 degrees. So you can have a quadrilateral with three right angles but its fourth angle will also be a right angle. So exactly 3 right angles is not possible.
No, it is impossible to draw an equiangular right triangle. An equiangular triangle has three 60o angles. A right triangle has one 90o angle, and two 45o angles.
It would be impossible. A trapezoid can't have three right angles. It would just make a rectangle.
On a sphere you can draw a triangle with three right angles. . At the North pole , zero meridian and its right angle 90 oW merdian. Draw these meridians to the Equator, and you will find they both meet the Equator at 90 o (degrees).
First you draw a square. A square has 4 right angles. If you draw a line above one of the right angles and rub out the angle which you have drawn a line above you have a pentagon with 3 right angles.
If you select one vertex of a heptagon and draw diagonals to all other vertices, you will divide the heptagon into 5 triangles such that the interior angles of the heptagon add up to the same sum as the interior angles of the five triangles.Now the sum of the interior angles of one triangle is 180 degrees. So for 5 triangles you get 5*180 = 900 degrees.In general, the interior angles of a polygon with n vertices is (n - 2)*180 degrees.
Draw a square