answersLogoWhite

0


Best Answer

Two lines cannot be parallel and perpendicular at the same time.

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you draw parallel perpendicular bisector?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is not a characteristic of of a perpendicular bisector?

is parallel-apex


How do you draw a perpendicular bisector of an angle?

The right way


Can a pair of parallel lines form a perpendicular bisector?

No, they cannot.


The first step in the construction of a perpendicular bisector is to draw a?

equilateral triangle ;)


You can draw a perpendicular bisector to a segment using paper-folding constructions?

true.


What do you need to do to prove a line is an angle bisector of an angle?

Draw a perpendicular to that line and extend the arms of the angle to meed the perpendicular drawn earlier. Check if the line is bisecting the perpendicular, if yes, then the line is a bisector of the angle. :)


What is the difference between and angle bisector and a perpendicular bisector?

An angle bisector bisects an angle. A perpendicular bisector bisects a side.


You can draw a perpendicular bisector to a using paper-folding constructions?

haterz gonna hate but it is yes


What can not form a perpendicular bisector?

A circle cannot form a perpendicular bisector.


How do you draw two parallel lines using only a straightedge and a protractor?

Draw a line. Draw a perpendicular to that line then a perpendicular from that one.


State the Perpendicular Bisector Theorem and its converse as a biconditional?

Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.


If a point is equidistant from the two sides of an angle then it is?

on the perpendicular bisector