0
It can't actually be eliminated, although you could re-express the equation in a way that no longer uses a power of two:
y2 = x
(y2)1/2 = x1/2
y = x1/2
If you don't want to write it with an exponent at all, you can also express it using a radical:
y = √x
But note that you're not actually eliminating the exponent. You're actually just re-expressing it in a slightly different notation.
What else can I help you with?
Is this a function x equals y2?
Yes, as x-y2=0
What is the value of 3x2 - y2 if x equals -1 and y equals 3?
x = -1y = 33x2 - y2 = 3 (-1)2 - (3)2 = 3 (1) - 9 = -6
Which choice shows y2 in isolated form x plus 4 2 plus y2 equals 22?
y^2=-x^2-8x+6
X2 plus y2 equals 13 where y equals 2?
If y=2 then that means x^2=9 and x= 3 or -3
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
If xy equals x2 plus y2 plus 2xy?
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
What is the radius of x2 plus y2 equals 9?
X2 or 2 times x?
How do you find the point of intersection between x2 plus y2 equals 5 and x-y equals 1?
x-y = 1 => x = y+1 x2+y2 = 5 => (y+1)(x+1)+y2 = 5 2y2+2y-4 = 0 y = -2 or y = 1 So the points of intersection are: (-1, -2) and (2, 1)
If SinA equals minusxdividedy then cosA equals?
sin A = -x/y Since the sine is the ratio of the opposite leg to the hypotenuse, let's assume the opposite leg's length is -x and the hypotenuse's length is y. Let's call the adjacent leg's length z. So: (-x)2+z2=y2 z2=y2-(-x)2 z2=y2-x2 z=√(y2-x2) cos A = z/y = √(y2-x2)/y
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
If y equals -2 when x equals 4 find x when y equals 5?
x1:y1 = x2:y2 4:-2 = x2:5 x2 = (4*5)/-2 x2 = -10
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
