If "jmoojn" is the moon then the event has already happened and it was not you. So it is impossible and therefore the probability is 0.
The probability of two people's birthday being the same is actually more likely than many would think. The key thing is to note that it doesn't matter what the first person's birthday is. All we need to work out is the probability that the second person has a birthday on any specific day. This probability is 1/365.25 The probability that they were born on June 10th is 1/365.25. The probability that they were born on February 2nd is 1/365.25 and the probability that they were born on the same day as you is 1/365.25
If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.
The probability that the second coin matches the first is 0.5 .The probability that the third coin matches the first is 0.5 .The probability that the second and third coins both match the first is (0.5 x 0.5) = 0.25 = 25%
What is the probability of rolling a 6 the first time and a 1 the second time
The probability that you will roll doubles on a pair of dice is 1 in 6. The probability that you roll "something" on the first die is 1 in 1. The probability that the second die will match the first die is 1 in 6. The resultant probability is simply the product of (1 in 1) and (1 in 6).
Adam Smith
No, da Vinci was not the first person to explain why the sky is blue. John Tyndall was the fist person to begin to explain this phenomenon in 1859.
me
William Harvey
Maybe scientist(s)
----------------------------------------------------------------------------------------------------------- ANSWER: Depends on the first supervisor's age and interests. -----------------------------------------------------------------------------------------------------------
First, are you sure that he's wrong and you're right. Then explain it nicely and try to lead the person to understand by himself.
The probability that there are 1,2,3 or 4 men is 1-(the probability that no men are selected). First we select the first person. The probability that this person is a woman is 5/10=1/2. For second person it is 4/9, then 3/8 and finally 2/7. We multiply these together: (1*4*3*2)/(2*9*8*7)=24/1008. This is the probability that every single person in the committee is a woman. One minus that probability is 984/1008=41/42 which is 97.619% Read more >> Options >> http://www.answers.com?initiator=FFANS
The probability of two people's birthday being the same is actually more likely than many would think. The key thing is to note that it doesn't matter what the first person's birthday is. All we need to work out is the probability that the second person has a birthday on any specific day. This probability is 1/365.25 The probability that they were born on June 10th is 1/365.25. The probability that they were born on February 2nd is 1/365.25 and the probability that they were born on the same day as you is 1/365.25
Ellen Kim was the first to explain why the sun and stars move across the sky in 1858
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
Let us assume that there are exactly 365 days in a year and that birthdays are uniformly randomly distributed across those days. First, what is the probability that 2 randomly selected people have different birthdays? The second person's birthday can be any day except the first person's, so the probability is 364/365. What is the probability that 3 people will all have different birthdays? We already know that there is a 364/365 chance that the first two will have different birthdays. The third person must have a birthday that is different from the first two: the probability of this happening is 363/365. We need to multiply the probabilities since the events are independent; the answer for 3 people is thus 364/365 × 363/365. You should now be able to solve it for 4 people.