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Q: How do you factor 11xsquared plus 25x - 24?

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The problem is 11x2 + 25x - 24. First, you check to see if there is any common number that can be factored out. There isn't. Then, you see what the factors of 11 are. 11 is a prime number, so there is only 11 and 1 that multiply to form eleven. Set up your two equations like this. (11x [leave this blank]) (x [leave this blank]) Now we're looking for numbers that multiply to give you -24. You could have -1 and 24, -2 and 12, -3 and 8, -4 and 6, -6 and 4, -8 and 3, -12 and 2, and -24 and 1. After some careful thought and mental math, you should find that -8 and 3, once you factor in the 11, should be the right fit. Try it out. (11x -8) (x + 3) 11x2 + 33x - 8x - 24 11x2 + 25x - 24 Then take these two equations and solve for x. 11x - 8 = 0 x = 8/11 x + 3 = 0 x = -3 And that gives you your answer. It takes a lot of practice to get it quickly - a lot of your tries won't give you the right answer. Just keep trying and you'll get the hang of it.

Factorise to (x-1)(x-24)=0 then either x-1 = 0 or x-24 = 0 so x=1 or x=24

(3x+12)(5x+2)

2x+5x-24 7x2-24

(5x - 3)(x + 8)

Divide both terms by 24. 24(9x3 +1)

8(a + 3)

24(w + z)

24(k + 4)

(s+3)(5s+8)

3(y + 4)(y + 2)

(5x + 6)(x + 4)

x2 + 10 - 24 = (x + 12)(x - 2)

The GCF is 6.

24 + 9 = 33. Then, 33 is itself the greatest common factor without other given value.

-8x+24 {This answer may be wrong: I think the question was intended to read, "Factor x2 - 10x + 24?" If so, the factors are (x - 6) and (x - 4)}

X + 4 is a factor of x^3 + 3x^2 - 10x - 24 along with (x + 2) and (x - 3)

x2 + 26x + 48 = (x + 24)(x + 2)

x2 - 11x + 24 = (x - 3)(x - 8)

2(x + 3)(x^2 + 4)

(x - 6)(x + 4)

(y-12)(y-2)

(3n-8)(n-3)

6y6

(x + 8)(x - 3)