Study guides

Q: How do you factor 256 into a product pf primes?

Write your answer...

Submit

Related questions

Pf is the symbol for Power Factor.

The formula you are looking for is W = I x E x pf. (pf = power factor).

When voltage and current waveforms are out of synch the power factor is reduced. In a pure resistance load the PF is 1. When inductance and capacitance is involved the PF is from 0 to 1.

Power factor measures the phase difference between voltage and current. If they are in phase the Power Factor is one. If the current and voltage are out of phase the power factor is between zero and one. You can describe the PF by saying the current lags the voltage with a PF = .8 or the voltage leads the current with a .8 PF.

0.5 lead PF or Power Factor means that the signal is ahead of the input voltage by a factor of 90 degrees. The lagging PF means it falls behind the input signal. In sinusoidal signals 0.5 lead or lag will be the same.

when lagging Power Factor changes to leading PF, then the voltage across the circuit in which capacitor bank is connected, is increased.

To determine and correct PF to unity. Leading or lagging PF costs money to businesses correcting PF usually to 0.99 is an efficiency drive

You would have to know the Power Factor, normally designated PF. MVA x PF = MW. If the PF is unity then MVA = MW. A PF of UNITY suggest the load is purely resistive with neither capacitive nor inductive components in the load or source. Of course this can mean such components have been balanced artificially.

It depends on the power factor. If the PF = 1, then you need 75kVA. In general, kVA needed = 75kW/PF.

Watts are the product of amp x volts. 200 x 110 = 22000. The above is correct for a pure resistive load. With an inductive load the formula is Watts = Volts x Current x PF Where PF = Power factor which is between 0 and 1. For definition of Power Factor, search wikipedia.com

You calculate power by multiplying voltage x current x Power Factor (PF). PF = 1 for a resistive load so you essentially convert maximum power with a resistive load. With an inductive load the PF decreases from 1 toward zero. Hence the lower the power factor the less efficient the system. This reduced PF is caused by the current and voltage sine waves being out of phase. If they are 180 degrees out of phase you have zero PF. PF correction involves circuitry that basically helps "tune" the circuit to reduce the lag. Capacitors are involved heavily in this process to tune the circuit.

Watts = Amps x Volts x 1.73 x pf. pf is the power factor.

KVA is the vector sum of real and reactive power; put differently, KVA at a specified power factor will tell you how many KW you have: KW = KVA * pf You must provide a power factor or power factor angle (if angle, replace pf with cos (pf) in above equation) or total reactive power to calculate.

The formula you are looking for is kW = amps x volts x 1.73 x pf / 1000. where kW means 'kilowatts' and pf means 'power factor'.

The formula you are looking for is Amperage = kw x 1000/1.73 x Voltage x pf. pf is power factor. Use .9 as a reference for power factor.

The ratio of active power (real power) and apparent power is called power factor ( pf ). Power Factor ( pf ) = Active Power / Apparent Power = .................. ( kvar )

Power factor = cos (angle)PF=cos @

PF = pressure base at which volume or Btu factor is being converted from PT = pressure base at which volume or Btu factor is being converted to Mcf@PF times (PF divided by PT) = Mcf@PT 1000Mcf @ 14.73 times (14.73 divided by 14.65) = 1005Mcf @ 14.65

Single phase W = V * A * PF (power factor) Three Phase W = 1.732 * V * A * PF

This conversion is dependant of power factor. Kw = kVA x PF. So assuming 0.8 pf it'l be 800 watts

To answer this question a voltage and pf (power factor) must be stated. kW = I x E x pf/1000.

Single phase formula for you to use kW = I x E x pf/1000. Three phase kW = I x E x 1.73 x pf/1000. pf = power factor. Use .9 for pf and the answer will be close.

69 = 3 x 23

Power factor (PF) varies between 1 and zero. It is 1 for a pure resistive load. The closer to one the more efficient the system. Hence the ideal is to get PF to one. This isn't possible with an inductive load which causes current and voltage to be out of phase. Various circuits are used to try and correct PF to 1 to increase efficiency.

The power factor is a measure of the phase difference. If they are exactly in phase the PF = 1. If they are 180 degrees out of phase PF = 0.