(13x^2 - 4y)(2x^2 - 5y)
ça ne marche pas...
4x + 20y
-6
If: 9y-20y = 25 Then: y = -25/11
8x + 20y
It is a straight line equation that needs to be rearranged into slope-intercept form as follows:- 8x+20y = -80 20y = -8x-80 y = -0.4x-4
x2 + 10x + y2 + 20y - 19 = 0 x2 + 10x + y2 + 20y = 19 Complete the squares on the LHS: x2 + 10x + 25 + y2 + 20y + 100 = 19 + 25 + 100 = 144 Simplify LHS: (x + 5)2 + (y + 10)2 = 122 This is the equation of all points whose distance form the point (-5, -10) is 12 units. That is, the circle with centre (-5, -10) and radius = 12 units.
x isn't in the calculation so it cant be solved.
You need at least two terms to find a GCF.
12y - 4 = 7y + 165y = 20y = 4
LCM(20y, 14y^2) = 140y^2
If: 3x-y = 5 and 2x2+y2 = 129 Then: x = 5/3+y/3 and so 2(5/3+y/3)2+y2 = 129 => 50+20y+2y2+9y2 = 1161 Therefore: 11y2+20y-1111 = 0 Solving the quadratic equation: y = -11 or y = 101/11 By substitution points of intersection are: (-2, -11) and (52/11, 101/11)