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There is no rational factorisation.
(2x - 3)(x + 2)
(x - 1)(2x - 9)
(x - 2)(2x + 7)
(2x-3)(x-1)
(x - 2)(2x - 3)
(2x - 9)(2x - 9) or (2x - 9)2
(x + 3)(3x - 2)
2x(2x - 1)
2x squared - 5x - 3 = (2x +1)(x -3)
(4x - 3)(2x + 3)
(2x - 1)(5x + 8)
(x - 1)(5x + 7)