(x + 3)(7x^2 + 1)
21x2 + 27x - 30 = 3*(7x2 + 9x - 10) = 3*(7x2 - 5x + 14x - 10) =3*[x*(7x - 5) + 2*(7x - 5)] = 3*(7x - 5)*(x + 2)
No, 2 x 3 x 7 = 42
40-42+5 -2+5 3 3 is the answer
No. 7*3, alone, is bigger than 12.
7X^3 Third degree polynomial.
-3
2x4 - 7x3 + x2 + 7x - 3 = (x + 1)(2x3 - 9x2 + 10x - 3) = (x + 1)(x - 1)(2x2 -7x + 3) = (x + 1)(x - 1)(x - 3)(2x -1)
the answer is 21 3 x 7 = 21
The polynomial 7x3 + 6x2 - 2 has a degree of 3, making it cubic.
42 = 2 × 3 × 7
7x3=21
I take this to be 3x3 - 21x2 + 36x. I notice that 3x is a factor common to all three terms. Let me remove that first. 3x ( x2 - 7x + 12 ) "By inspection" I can make up the two factors in the parenthesised part. 3x ( x - 4 ) ( x - 3 )