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Q: How do you factor 8x3-8x2 plus 8x?

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That does not factor neatly.

-8x + 3x2 - 3

x2 + 8x + 15 = (x + 3)(x + 5)

x2 + 8x + 15 = (x + 3) (x + 5).

This is not factor-able.

8x(x+9)

x2 + 8x = x(x+8)

2x^2(x - 2)(x - 2)

(x + 1)(3x + 5)

(x + 6)(x + 2)

It is: 2(4x+5)

You don't. There is no way to factorise it.

8(x + 1)

The only factor is 2. 2*(t3 + 2t2 + 4x)

9x2 + 8x - 1 = (9x - 1)(x + 1)

(8x + 9)(3x^2 - 1)

x2-8x+15 = (x-3)(x-5)

(x + 5)(x + 8)

4(x + 1)(x + 1)

(x+1)(x+7)

4(x^2 + 2x + 8)

2x(x2+2x+4)

No because the discriminant is less than zero.

(4x + 1)(2x + 3)

x + 4