(a + b)(r + s)
4d2+16 4(d2+4)
10x2-36x+18 Divide all terms by 2: 5x2-18x+9 = (5x-3)(x-3) when factored
Take out the common factor, 3: 3x + 6 = 3(x + 2).
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-1 plus or minus the square root of 265) divided by 12 x = 1.2732350496749756 x = -1.439901716341642
(20x + 3)(1x + 1)
2(5x + 3y)(2x + 5y)
(2x+1)(2x+3) when factored
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(3x + 4)(3x + 4)
(x + 8)(x + 1)
(x+1)(x+9)
no
20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y) = (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)
20x2 - 3x + 10 does not have any real factors.
(x-2)(x-3)
(x-3)(x+8)