Q: How do you factor out 5a2 7a 2?

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4a - 5a^2

The factorization of 5a^2 + 24a - 5 is (5a - 1)(a + 5).

4a-2=7a-6 4=3a a=4/3

(7a - 1)(6a + 1)

4a - 5 = 7a - 7 -5 = 3a - 7 2 = 3a a = 3/2

Related questions

-8/7a

solving by factoring 5a2

(5a2 - 3)(5a2 + 3)

Combine like terms, adding/subtracting the coefficients: (5a² + 6a + 2) + (7a² - 7a + 5) = (5+7)a² + (6-7)a + (2+5) = 12a² - a + 7 (5a² + 6a + 2) - (7a² - 7a + 5) = (5a² + 6a + 2) + (-7a² + 7a - 5) = (5-7)a² + (6+7)a + (2-5) = -2a² + 13a - 3

5(a2-3)

8a(5a2-1)

5a^2 - 5a - 60 ---- 5(a2 + a - 12)

The GCF is 7a.

5a(a+2b+b²)

Since 7a is a factor of 14ab, it is automatically the GCF.

7a 7a * 4 = 28a 7a * 7b = 49ab

Yes.