4a3 - 4a2 = 4a2*(a - 1)
If a is an integer then 4 divides 4a2 so it cannot be a prime. If a = 0 then 4a2 = 0 and cannot be simplified further If a = 1 then 4a2 = 4 = 2*2 If a is an integer > 1, then 4a2 = 2*2*a*a If a is not an integer, then there are too many possible options for the answer.
sqrt(4a2) = 21plus or minus (2a) = 21plus or minus (a) = 10.5a = +10.5a = -10.5
How do you solve 4y plus x equals 8
121 is the answer
a = [ 0, 4 ]
(2a + 1)(4a2 - 2a + 1)
4a2
Assuming multiplication, it's 4a2.
4a2+4ab+b2 in2
7a2(a + 1)(a - 1)(a2 + 1)
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
4a3 - 4a2 = 4a2*(a - 1)
If a is an integer then 4 divides 4a2 so it cannot be a prime. If a = 0 then 4a2 = 0 and cannot be simplified further If a = 1 then 4a2 = 4 = 2*2 If a is an integer > 1, then 4a2 = 2*2*a*a If a is not an integer, then there are too many possible options for the answer.
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
sqrt(4a2) = 21plus or minus (2a) = 21plus or minus (a) = 10.5a = +10.5a = -10.5
4a2