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Q: How do you factor x2-y2 plus 7x plus 7y?

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7x + 8y

(4x2)+ (28xy) + (49y2) = (2x + 7y)(2x + 7y) = (2x + 7y)2

the answer to this problem is -2x^2y^2

y^2 + 7y + 12 = (y+4)(y+3)

7y

The GCF is 7.

7y+3x-21 =0 7y = -3x+21 y = -3/7x+3 The y intercept is 3

(y + 5) (y + 2)

(x + 5y)(x + 7y)

7(y + 4)

8y + 7y = 15ySo [ 8y + 9 + 7y ] = 15y + 9If you want to get fancy and factor that expression, it's 3(5y + 3) .

a + 7y

5x(6x + 7y + 8)

-8(x - 7y)(x + 2y)

(3x - 7y)(2x + 9y)

(7y - 5)(y + 1)

(2x - 3y)(2x - 7y)

21-7y+3x-xy7(3-y)+x(3-y)

y = 6/7x+3 General form of the line equation: 6x -7y+21 = 0

-x + y = -7. There is nothing more that can be done with just one equation and two unknowns.

-7y + 4y = -3y

16+7y-8 = 7y+16-8 = 7y+8

7x-y-28 = 0

(7y + 2)(7y - 2)

If: 2x-7y = 20 Then: y = 2/7x -20/7 which is now in slope-intercept form