It is: 3y and y
(7y + 2)(7y - 2)
If that's + 28, the answer is 7(y + 4)
(y + 3)(y - 10)
Do you mean some thing like 4x2 - 28xy + 49y2 ? notice 4x2 = (2x)2 and 49y2 = either (7y)2 or (-7y)2 (1st and last terms must be squares) and the middle term is 2(2x)(-7y) (2 times sq root of 1st times sq root of last) Once the pattern is recognized: (sq root 1st + sqroot 2nd)2 or (sq root 1st - sqroot 2nd)2 depending on if middle term is positive or negative. So, back to my example: 4x2 - 28xy + 49y2 = (2x - 7y)2 because middle is negative. Simpler example factor x2 + 6x + 9. 1st and last are both squares sq root of 9 = 3 3 times 2 = 6 that fits the middle so x2 + 6x + 9 = (x + 3)2
y^2 + 7y + 12 = (y+4)(y+3)
8y + 7y = 15ySo [ 8y + 9 + 7y ] = 15y + 9If you want to get fancy and factor that expression, it's 3(5y + 3) .
(y + 5) (y + 2)
(x + 5y)(x + 7y)
7(y + 4)
-8(x - 7y)(x + 2y)
5x(6x + 7y + 8)
21-7y+3x-xy7(3-y)+x(3-y)
(2x - 3y)(2x - 7y)
(7y - 5)(y + 1)
(3x - 7y)(2x + 9y)
It is: 3y and y