Unfortunately, you can't. If it were x2 + 2x - 3 ... you could factor it into (x-1)(x+3). Hope I helped!
xx Morgan
Added:
X =[ - 2 (+/-) sqrt(- 8)]/2
would be the answer in complex fashion and and i, imaginary number answer would be forthcoming.
Two is a prime factor of that equation.
17.
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
no
4
Factor out -2: -2(x squared +11x-20). This is fully factored.
it is 2y squared + 3y
(x-1)(x+2)
x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
(a - 2)(a^2 + 6)
By factoring I get x-3 divided by x+3
c2 - 6cd + 9d2 - 4 The first three terms are a complete square = (c - 3d)2 - 4 Difference of two squares = (c - 3d + 2)(c - 3d - 2)