(x - 9)(x + 9)
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
8
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
x2-2x-10-5 = 0 x2-2x-15 = 0 (x+3)(x-5) = 0 x = -3 or x = 5
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
15z² - 22z - 5 = 0 → (5z + 1)(3z - 5) = 0
0. Power factor has to do with the amount of real power. if you have a purely capacitive load, there is no real power flow, thus pf = 0. For purely resistive load, power factor will be 1.0.
Let y= ab+(- a)(b) +(-a)(-b) factor out -a y= ab+(-a){b+(-b)} y=ab+(-a)(0) y =ab -------------------(1) now factor out b y= b{a+(-a)}+(-a)(-b) y= b(0) +(-a)(-b) y= (-a)(-b)-----------------(2) equate (1) and (2) (-a)(-b)=ab minus x minus = positive
10 is a root of x3 - 1000 = 0, so (x-10) is a factor. Use long division (x3 - 1000)/(x-10) to find x2 + 10x + 100, as the other factor.
33 - 100 = 26
The power factor of a purely resistive circuit is 1.0.
3m^2 - 9m = 0 factor out 3m 3m(m - 3) = 0 m = 0 -------- or m = 3 --------