There is a formula for the "difference of squares." In this case, the answer is
(x7 - 7)(x7 + 7)
49 - 8 - 6 = 35
49 - 8 - 6 = 35
9x^(2) - 49 Re-write as two squared terms. (3x)^(2) - 7^(2) This will factor to ( 3x - 7)(3x + 7) Note the two different signs.
(x - 7)(x2 + 7x + 49)
The only prime factor of 49 is seven (7).
(8w + 7)(8w - 7)
101 minus 49 is 52.
-49 minus 75 is -124
x4-49 is the difference of two squares when factored as (x2-7)(x2+7)
(x - 7) is.
(xy - 7)(x^2y^2 + 7xy + 49)
2011 - 49 = 1,962