In order to factor this expression we are going to write it as 2 expressions (factors) which when multiplied together equal x2 - 13x + 42.
We can see straight away that the simplest way to end up with x2 is to have an "x" in each factor.
This then just leaves us to find two numbers which when added together result in -13 and when multiplied result in 42.
It likely will not take you too long to see that -6 & -7 would do this.
Thus we can factor this to:
(x-6) (x-7)
6(x + 7)
The expression cannot be factorised.
common factor is 42. so it's 35/42 + 24/42 = 59/42 = 1&17/42
3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).
It is: (x+7)(x-6) when factored
(x + 7)(x - 6)
44
(s + 6)(6s - 7)
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
An unnecessary one. 42 + 96 = 138
6 is a factor of 42.
28 is not a factor of 42.