To factorise the expression (10x - 6z), first identify the greatest common factor (GCF) of the coefficients, which is 2. You can then factor out 2 from each term: (10x - 6z = 2(5x - 3z)). Thus, the factorised form is (2(5x - 3z)).
you do (245x)
-5
(x + 6z)(x - 6z)
6z + 28 = 12z + 10 18 = 6z 3 = z
Firstly, we got:(-6z) (102)(-6) (102) (z)-612z-612z is the answer.
you do (245x)
-5
-5
5(3-2x)
-5
(x-7)(x-3)
It is 2(2x+3) when factorised
x^2 - 10 x + 25 = (x - 5)(x - 5)
6z =
8x2 - 10x - 3 = (2x - 3)(4x + 1)
6z-513 = -507
-5x+7y-6z