x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
x^2 - 10 x + 25 = (x - 5)(x - 5)
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
x2 + 10x + 21 = (x + 3)(x + 7)
(x2+10x+21)/(x+3) = (x+7)
x2+10x+21 = (x+3)(x+7)
Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
x2+10x-336
X2 + 4xx(x + 4)=======
x2 + 6x = x*(x + 6)
x2+10x+21 = (x+3)(x+7) when factored.....
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
x^2 - 10 x + 25 = (x - 5)(x - 5)
4(x2 + 4)