0
87^x = 0.5
take the log of both sides:
log(87^x) = log(0.5)
according to one of the log laws, you can move exponents to the front of the log function, so:
x(log87) = log(0.5)
so, then you have to get x by itself, so divide...
x = log(0.5)/log(87)
x= -0.1552
so, to prove this:
87^(-0.1552)= 0.499997
(Close enough, I just rounded in the middle, but this answer would be more than acceptable)
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∙ 13y ago
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