Two ways: The interior and exterior angles add up to 180. That makes the exterior angles 6. The exterior angles total 360. That means there are 60 sides.
Second way: The total of the interior angles is 180(n - 2) 180 times 58 is 10,440. 10440/60 = 174
A polygon with any number of sides can have a 156 degree angle, as can most non-polygonal plane shapes.
120 sides
(n-2)*180 = sum of interior angles when n is the number of sides of the polygon
Any polygon can have a 40-degree angle. It doesn't have to, but it can.
Any polygon can have a 50-degree angle. It doesn't have to, but it can.
Any polygon can have a 130-degree angle. It doesn't have to, but it can.
remember this formula for the number of sides = n sum of internal angles of a regular polygon = [2x(n-2)x90 degree] each interior angle of a regular polygon = [2x(n-2)x90 degree]/n each exterior angle of a regular polygon = 360 degree/n for your question: each exterior angle of a 15 sided regular polygon = 360 degree/15 = 24 degree
A regular octdecagon (18 sided geometric figure) was internal angles of 160 degrees.
18
The answer is 14agon.
1440 degrees
The sum of angles of a regular polygon in degrees = 180(n - 2), where n is the number of sides of the regular polygon. So, where n = 8 the sum of angles in degree = 180(8 - 2) = 180(6) = 1,080 Angle in degree = (The sum of angles in degree)/n Angle in degree = (1,080)/8 = 135 Thus, in a regular octagon, the degree of an angle is 135.