The LCM of two numbers multiplied by their GCF will equal the product of the original numbers. If you know the LCM, divide it into the product. The result will be the GCF.
Knowing the LCM of the denominators of unlike fractions will help you find the least common denominator, a necessary step in adding and subtracting them. Knowing the GCF of a numerator and denominator will tell you if the fraction can be reduced.
The GCF is 4a2b The LCM is 12a3b2
Knowing the LCM will help when adding or subtracting unlike fractions. By finding the LCM of the denominators, (called the lowest common denominator) you can convert unlike to like fractions and proceed with the adding or subtracting. Knowing the GCF helps reduce a fraction. By finding the GCF of the numerator and the denominator and dividing both of them by it, you can reduce a fraction to its lowest terms (simplest form). If the GCF is 1, the fraction is in its simplest form. You can successfully multiply fractions without knowing the GCF or LCM.
You need at least two numbers to find either an LCM or a GCF.
Finding the GCF helps to reduce fractions to their simplest form. Knowing the GCF can help to find the LCM, which assists in adding and subtracting fractions.
The LCM is: 825The GCF is: 5
To find the GCF and LCM at least two or more numbers must be given
To find the LCM and GCF of numbers at least two or more numbers are neeeded.
You need at least two numbers to find either a GCF or an LCM.
The GCF of two numbers multiplied by their LCM will equal the product of the original numbers. If you know the GCF, divide it into the product of the two. The result will be the LCM. If the GCF of two numbers is 1, the LCM is their product.
To find the GCF and the LCM you have to first at least try to use prime factorization. So use factor trees. Or for the LCM find th least common multiples of the number.
#include<stdio.h> main() { int a,b,i,lcm,gcf; printf("\n Enter two numbers"); scanf("%d%d",&a,&b); for(i=0;i<=a;i++) { if((b%i==0)&&(a%i==0)) { gcf=i; } } lcm=a*b/gcf; printf("\n GCF is %d and LCM is %d",gcf,lcm); }