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Q: How do you find a prime factor of 59using a t?

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The only prime factor of 16 is 2.

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If you are trying to find a factor of a number n, then there is no need to search beyond s = sqrt(n). For if a factor of n is greater than s, then its factor pair will be less than s and so you should have found that already.For proof, let u be the factor pair. That is, t*u = n. Also s*s = n so that t*u = s*sDivide both sides by u*s so that t/s = s/uNow, t > s implies that t/s > 1 and so s/u > 1 which means that s > u.

Given I<T, the accumulation factor A(I,T) is the accumulation value at the time T of one unit of money invested at time I. So for compound interest A(I,T)= (1+i)^(T-I).

T(t + 4)

The program is as follows: #include <stdio.h> void main() { int number = 0; int count = 1; int i = 0; printf("Enter the number whose prime factor is to be determined: \t"\n); scanf("%d", &number); while((number /2) > ++count) { if(number % count == 0) { printf("factor = [%d]\n", count); } } }

(defun prime (num) (if (< 2 num) (do ((dividend 2 (1 + dividend)) (chk-to (sqrt num))) ((equal (rem num dividend) 0)) (when (<= chk-to dividend) (return t))) t))

(t-8)(t + 3)

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