How do you find a slope-intercept form of an equation passing through another point?

Answer 1

Assuming that you are given another equation and need to find another equation in slope-intercept form passing through a given point. --- Ex. Find the equation of a line passing through (2, 5) and parallel to y = 3x -7. 3x means the slope is 3 and parallel means the new slope will be the same.

use y = mx + b, substitute the point (2, 5) for x and y and substitute 3 for the slope, m. you get:

y = mx + b

5 = 3(2) + b

5 = 6 + b

-1 = b

Now reuse y = mx + b and substitute m = 3 and b = -1 but leave y and x as variables to get the answer:

y = 3x -1

There are other ways to do this so you probably need to see if this is the method that your teacher wants.